10p^2=28p-6

Solution for 10p^2=28p-6 equation:

10p^2=28p-6

We move all terms to the left:

10p^2-(28p-6)=0

We get rid of parentheses

10p^2-28p+6=0

a = 10; b = -28; c = +6;
Δ = b2-4ac
Δ = -282-4·10·6
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{34}}{2*10}=\frac{28-4\sqrt{34}}{20}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{34}}{2*10}=\frac{28+4\sqrt{34}}{20}
$